Friday, April 13, 2012

CUT-OFF Marks for IIT-JEE 2012 revealed

According to a news report published in the newspaper Hindustan Times ( New Delhi Edition, Page No. 13, Dated 11April 2012) the IITs have declared, for the first time in the history of IIT-JEE, the minimum qualifying marks in each subject and also the minimum qualifying aggregate that a student must secure in the JEE-2012 to be included in the rank list.

The details of the declared cut-offs are as under:


CATEGORY

AGGREGATE CUT-OFF

INDIVIDUAL SUBJECT CUT-OFF

General

35% of the total marks (408)

14 marks each in physics, chem, and maths

OBC

31.5% of the total marks (408)

13 marks each in physics, chem, and maths

SC/ST/PD

17.5% of the total marks (408)

7 marks each in physics, chem, and maths

List of All My Articles: Go to this page to read all the articles written by me for students who are preparing for IIT-JEE and PMT

1 comment:

Anonymous said...

Sir, I am studying in XII in CBSE syllabus.In your articles you have written about the importance of ncert text books. But ,in physics, I have seen that some of the proofs of derivations given in reference guides or by tuition teachers seems to be easier.Will I get marks if I study such derivations for board exam? Also, I have not prepared for the XII board that is fast approaching. Am I too late to start learning to get good marks? Or will I be able to take an improvement exam? Thank you